2=-16t^2+24t+4

Solution for 2=-16t^2+24t+4 equation:

2=-16t^2+24t+4

We move all terms to the left:

2-(-16t^2+24t+4)=0

We get rid of parentheses

16t^2-24t-4+2=0

We add all the numbers together, and all the variables

16t^2-24t-2=0

a = 16; b = -24; c = -2;
Δ = b2-4ac
Δ = -242-4·16·(-2)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{11}}{2*16}=\frac{24-8\sqrt{11}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{11}}{2*16}=\frac{24+8\sqrt{11}}{32}
$